configure la-agg-port 1 selection-policy mac-src actor-key 11 aggregatable aggregatable lacp-mode enable-lacp active-lacp passive-lacp configure la-agg-port 5 selection-policy mac-src actor-key 11

语句 SELECT IF（-1，5，2）的返回值是（ ）。 中有如下命令序列： SELECT A USE DEMO1 SELECT B USE DEMO2 SET RELATION TO RECNO（）INTO A SELECT C USE DEMO3 SET RELATION TO RECNO（）INTO B SELECT B GO 8 ？ RECN0（），RECNO（），RECNO（）执行此段之后，屏幕显示的记录号是 In a test database, you issue the SELECT … INTO OUTFILE statement to create a file with your t1 table data. You then TRUNCATE this table to empty it.（） Mysql＞ SELECT * INTO OUTFILE '/tmp/t1.sql' from t1; mysql＞ TRUNCATE t1; For Question 1, select one answer choice.　 The author of the passage is primarily concerned with ______. HTML 代码表示(   )。   SELECT语句中，__1__子句用于选择满足给定条件的元组 SELECT语句中"SELECT DISTINCT"表示查询结果中 For Question 1, select one answer choice.　 In the passage, “gold standard” most nearly means ______. Evaluate the SQL statement: SELECT ROUND(45.953, -1), TRUNC(45.936, 2) FROM dual; Which values are displayed? （） In a SELECT statement that includes a WHERE clause, where is the GROUP BY clause placed in the SELECT statement?（） In a SELECT statement that includes a WHERE clause, where is the GROUP BY clause placed in the SELECT statement? （） 查询同时存在” 01 “课程和” 02 “课程的情况 select * from（select SC.SId, SC.score from SC where SC.CId = ’01’） as t1 inner join（select SC.SId, SC.score from SC where SC.CId = ’02’） as t2 on t1.SId = t2.SId（） 在SQL中，SELECT语句的“SELECT DISTINCT”表示查询结果中（ ）。 Evaluate the SQL statement:SELECT ROUND(TRUNC(MOD(1600,10),-1),2)FROM dual;What will be displayed?（） Evaluate the SQL statement: SELECT ROUND(TRUNC(MOD(1600,10),-1),2) FROM dual; What will be displayed?（） 条件子句WHERE 工资＞ALL（SELECT 工资 FROM 职工 WHERE 部门号=1）的含义为（） 在SQL语言的SELECT语句中，“SELECT DISTINCT”表示查询结果中______。 Practical assignment: look up the amount of protein in the following foods and select the 3 items that contain less than 1% protein. SELECT语句中，与0个或多个字符匹配的通配符是__1__ 查询” 01 “课程比” 02 “课程成绩高的学生的信息及课程分数 select * from（select SC.SId, SC.score from SC where SC.CId = ’01’） as t1 inner join（select SC.SId, SC.score from SC where SC.CId = ’02’） as t2 on t1.SId = t2.SIdwhere