2025年高职单招《数学(中职)》每日一练试题05月27日
<p class="introTit">单选题</p><p>1、已知<img src="https://img2.meite.com/questions/202409/1366e3e0ae0f489.png" />则cos2α=()</p><ul><li>A:<img src='https://img2.meite.com/questions/202409/1366e3e0b5c4fdc.png' /></li><li>B:<img src='https://img2.meite.com/questions/202409/1366e3e0bc20c0f.png' /></li><li>C:<img src='https://img2.meite.com/questions/202409/1366e3e0c2ec954.png' /></li><li>D:<img src='https://img2.meite.com/questions/202409/1366e3e0c83d981.png' /></li></ul><p>答 案:C</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1366e3e0d286cbe.png" /><img src="https://img2.meite.com/questions/202409/1366e3e0d6936db.png" /></p><p>2、“a-b=0”是“a²-b²=0”的()
</p><ul><li>A:充分不必要条件</li><li>B:必要不充分条件</li><li>C:充要条件</li><li>D:既不充分也不必要条件</li></ul><p>答 案:A</p><p>解 析:由a<sup>2</sup>-b<sup>2</sup>=0得a=b或a=-b,由a-b=0得a=b,所以“a-b=0”是“a<sup>2</sup>-b<sup>2</sup>=0”的充分不必要条件.</p><p>3、函数<img src="https://img2.meite.com/questions/202409/1266e24e4d199c8.png" />的定义域为()</p><ul><li>A:(-∞,3]</li><li>B:[3,+∞)</li><li>C:(-∞,2]</li><li>D:[2,+∞)</li></ul><p>答 案:D</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1266e24e565b7f2.png" /><img src="https://img2.meite.com/questions/202409/1266e24e5adf8c8.png" /><img src="https://img2.meite.com/questions/202409/1266e24e5f754af.png" /><img src="https://img2.meite.com/questions/202409/1266e24e64ce7ac.png" /><img src="https://img2.meite.com/questions/202409/1266e24e6970398.png" /></p><p class="introTit">主观题</p><p>1、已知<img src="https://img2.meite.com/questions/202501/1167822ff243cf5.png" /></p><p>答 案:方法一:矢量图表示法 矢量图表示法如图所示。<img src="https://img2.meite.com/questions/202501/1167822ff89fe55.png" /><img src="https://img2.meite.com/questions/202501/1167822ffb0aba3.png" />
方法二:矢量表示法<img src="https://img2.meite.com/questions/202501/116782300184954.png" /></p><p>解 析:<img src="https://img2.meite.com/questions/202409/1366e3aff07aaa2.png" /><img src="https://img2.meite.com/questions/202409/1366e3affb6a19c.png" /><img src="https://img2.meite.com/questions/202409/1366e3affff2ae2.png" /></p><p class="introTit">填空题</p><p>1、设函数f(x)=a<sup>2x-1</sup>+5,若f(2)=13,则f(-1)=()</p><p>答 案:<img src="https://img2.meite.com/questions/202409/1266e24ff48cb2b.png" /></p><p>解 析:<img src="https://img2.meite.com/questions/202409/1266e24ffe6039d.png" /><img src="https://img2.meite.com/questions/202409/1266e25002c9ba4.png" /><img src="https://img2.meite.com/questions/202409/1266e25007a788e.png" /></p><p>2、3(2a-b)-5(a+3b)=()</p><p>答 案:a-18b</p><p>解 析:3(2a-b)-5(a+3b)=6a-3b-5a-15b=(6-5)a-(3+15)b=a-18b.</p><p>3、复数<img src="https://img2.meite.com/questions/202501/06677b75afcda4b.png" />()
</p><p>答 案:2i</p><p>解 析:<img src="https://img2.meite.com/questions/202501/06677b75c60bef1.png" /></p><p class="introTit">简答题</p><p>1、已知向量a=(1,-1),b=(2,3).
(1)求|2a+b|的值.
(2)当实数k为何值时,(a-2b)⊥(ka+b)?</p><p>答 案:<img src="https://img2.meite.com/questions/202409/1966ebca57ddc46.png" /><img src="https://img2.meite.com/questions/202409/1966ebca5e1aeb7.png" /><img src="https://img2.meite.com/questions/202409/1966ebca658b715.png" /><img src="https://img2.meite.com/questions/202409/1966ebca75f33b5.png" /></p>