2025年高职单招《数学(中职)》每日一练试题04月15日

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04/15
<p class="introTit">单选题</p><p>1、已知4<sup>a</sup>=3,b=log<sub>2</sub>3,则4<sup>a</sup><sup>-b</sup>=()  </p><ul><li>A:3</li><li>B:1</li><li>C:<img src='https://img2.meite.com/questions/202409/2166ee3c54056f4.png' /></li><li>D:<img src='https://img2.meite.com/questions/202409/2166ee3c5978fd5.png' /></li></ul><p>答 案:D</p><p>解 析:因为b=log<sub>2</sub>3,所以2<sup>b</sup>=3,所以4<sup>b</sup>=(2<sup>b</sup>)²=3²=9,所以<img src="https://img2.meite.com/questions/202409/2166ee3f14cec0d.png" /></p><p>2、已知向量a与b的夹角为60°,且|a|=2,|b|=4,则a•b=()</p><ul><li>A:8</li><li>B:<img src='https://img2.meite.com/questions/202409/1966ebc2eeef1e5.png' /></li><li>C:<img src='https://img2.meite.com/questions/202409/1966ebc2f8bb785.png' /></li><li>D:4</li></ul><p>答 案:D</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1966ebc2ffab8ba.png" /></p><p>3、<img src="https://img2.meite.com/questions/202409/1366e3fb600dc81.png" />的零点为()</p><ul><li>A:<img src='https://img2.meite.com/questions/202409/1366e3fb66bfe0c.png' /></li><li>B:<img src='https://img2.meite.com/questions/202409/1366e3fb6e6eac3.png' /></li><li>C:<img src='https://img2.meite.com/questions/202409/1366e3fb7ca2504.png' /></li><li>D:<img src='https://img2.meite.com/questions/202409/1366e3fb825ec99.png' /></li></ul><p>答 案:A</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1366e3fb8d00744.png" /><img src="https://img2.meite.com/questions/202409/1366e3fb90c3e10.png" /></p><p class="introTit">主观题</p><p>1、已知<img src="https://img2.meite.com/questions/202501/1167822ff243cf5.png" /></p><p>答 案:方法一:矢量图表示法 矢量图表示法如图所示。<img src="https://img2.meite.com/questions/202501/1167822ff89fe55.png" /><img src="https://img2.meite.com/questions/202501/1167822ffb0aba3.png" /> 方法二:矢量表示法<img src="https://img2.meite.com/questions/202501/116782300184954.png" /></p><p>解 析:<img src="https://img2.meite.com/questions/202409/1366e3aff07aaa2.png" /><img src="https://img2.meite.com/questions/202409/1366e3affb6a19c.png" /><img src="https://img2.meite.com/questions/202409/1366e3affff2ae2.png" /></p><p class="introTit">填空题</p><p>1、已知0是正方形ABCD的中心,则向量<img src="https://img2.meite.com/questions/202409/1966ebc4bca0148.png" />是().(填序号) ①平行向量;②相等向量;③有相同终点的向量;④模都相等的向量</p><p>答 案:④</p><p>解 析:根据向量的有关概念及正方形的性质,可得向量<img src="https://img2.meite.com/questions/202409/1966ebc4c0e21e0.png" />是模都相等的向量</p><p>2、当x>2时,<img src="https://img2.meite.com/questions/202501/06677b745d82323.png" />的最小值为____________</p><p>答 案:<img src="https://img2.meite.com/questions/202501/06677b746484382.png" /></p><p>解 析:<img src="https://img2.meite.com/questions/202501/06677b746c3dd55.png" /> 是定值,  故由均值定理得,<img src="https://img2.meite.com/questions/202501/06677b74857512a.png" />  当且仅当<img src="https://img2.meite.com/questions/202501/06677b748ccb947.png" /><img src="https://img2.meite.com/questions/202501/06677b7491c17a3.png" /> 有最小值<img src="https://img2.meite.com/questions/202501/06677b7497e0b8d.png" /></p><p>3、已知函数f(x)=x<sup>2</sup>+2x-3,<img src="https://img2.meite.com/questions/202409/1166e14debec35e.png" />若<img src="https://img2.meite.com/questions/202409/1166e14df442cdd.png" />则b-a的最大值()是</p><p>答 案:6</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1166e14e013c354.png" /></p><p class="introTit">简答题</p><p>1、已知椭圆<img src="https://img2.meite.com/questions/202409/1866ea41c653d9e.png" />的离心率为<img src="https://img2.meite.com/questions/202409/1866ea41ceb07f2.png" />,短轴长为 4.(1)求椭圆的标准方程;<br />(2)过点P(2,1)作椭圆C的弦,若弦被P平分,求此弦所在直线的方程.  </p><p>答 案:(1)由题意知<img src="https://img2.meite.com/questions/202409/1866ea7ee309c9d.png" />,2b = 4,a<sup>2</sup>=b<sup>2</sup>+c<sup>2</sup> 所以a=4,b=2,<img src="https://img2.meite.com/questions/202409/1866ea7f1334a70.png" /> 所以椭圆的标准方程为<img src="https://img2.meite.com/questions/202409/1866ea7f1c2d1b1.png" /> (2)设以点 P(2,1)为中点的弦与椭圆交于A(x<sub>1</sub>,y<sub>1</sub>),B(x<sub>2</sub>,y<sub>2</sub>)两点,则x<sub>1</sub>+x<sub>2</sub>= 4,y<sub>1</sub>+y<sub>2</sub>= 2. 因为<img src="https://img2.meite.com/questions/202409/1866ea7f58bb19c.png" /> 两式相减得(x<sub>1</sub>+x<sub>2</sub>)(x<sub>1</sub>-x<sub>2</sub>)+4(y<sub>1</sub>+y<sub>2</sub>)(y<sub>1</sub>-y<sub>2</sub>)= 0, 所以4(x<sub>1</sub>-x<sub>2</sub>)+8(y<sub>1</sub>-y<sub>2</sub>)= 0, 所以直线 AB 的斜率为<img src="https://img2.meite.com/questions/202409/1866ea7f931555e.png" /> 所以所求直线的方程为<img src="https://img2.meite.com/questions/202409/1866ea7fa732701.png" />,即x+2y-4=0.  </p>
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