2024年高职单招《数学(中职)》每日一练试题11月01日
<p class="introTit">单选题</p><p>1、设A,B 分别为椭圆<img src="https://img2.meite.com/questions/202409/1866ea3c4bcb3ef.png" />的左顶点和上顶点,F为C的右焦点,则F到直线AB的距离为()
</p><ul><li>A:<img src='https://img2.meite.com/questions/202409/1866ea3c5dd9eda.png' /></li><li>B:<img src='https://img2.meite.com/questions/202409/1866ea3c65a7f05.png' /></li><li>C:<img src='https://img2.meite.com/questions/202409/1866ea3c6bd6037.png' /></li><li>D:<img src='https://img2.meite.com/questions/202409/1866ea3c718a797.png' /></li></ul><p>答 案:A</p><p>解 析:由题意可得A(-2,0),B(0,<img src="https://img2.meite.com/questions/202409/1866ea45cda5e51.png" />),F(1,0),所以直线 A8 的方程为<img src="https://img2.meite.com/questions/202409/1866ea45dbab264.png" />,整理得<img src="https://img2.meite.com/questions/202409/1866ea45e3a8bde.png" /><img src="https://img2.meite.com/questions/202409/1866ea45f0a228d.png" />,所以F到直线AB 的距离<img src="https://img2.meite.com/questions/202409/1866ea4613e1d0b.png" /></p><p>2、若a,b,c为实数,且<img src="https://img2.meite.com/questions/202409/1066dfb4b3ba02d.png" />则下列结论错误的是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202409/1066dfb4bf539b3.png' /></li><li>B:<img src='https://img2.meite.com/questions/202409/1066dfb4c4be9bd.png' /></li><li>C:<img src='https://img2.meite.com/questions/202409/1066dfb4cb1a55c.png' /></li><li>D:<img src='https://img2.meite.com/questions/202409/1066dfb4d0c3f6b.png' /></li></ul><p>答 案:B</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1066dfb503dc744.png" /> 故A不符合题意;当c=0时不等式不成立,故B符合题意;<img src="https://img2.meite.com/questions/202409/1066dfb50ec580a.png" /><img src="https://img2.meite.com/questions/202409/1066dfb514270d4.png" />
故C不符合题意;<img src="https://img2.meite.com/questions/202409/1066dfb51d3dce6.png" /> D不符合题意.</p><p>3、若集合A={0,1,2,3},B={1,2,4},则AUB=()
</p><ul><li>A:{0,1,2,3,4}</li><li>B:{1,2,3,4}</li><li>C:{1,2}</li><li>D:{0}</li></ul><p>答 案:A</p><p>解 析:因为集合A={0,1,2,3}与B={1,2,4}的所有元素为0,1,2,3,4,所以AUB={0,1,2,3,4}.</p><p>4、函数f(x)=√3sinx-cosx的值域为()</p><ul><li>A:[-√3,√3]</li><li>B:[-√3-1,√3+1]</li><li>C:[-1,1]</li><li>D:[-2,2]</li></ul><p>答 案:D</p><p>解 析:易知<img src="https://img2.meite.com/questions/202409/2166ee3ba941fba.png" /><img src="https://img2.meite.com/questions/202409/2166ee3badbb548.png" />。因为<img src="https://img2.meite.com/questions/202409/2166ee3bb8e3771.png" /><img src="https://img2.meite.com/questions/202409/2166ee3bc1b16a0.png" />,所以函数f(x)=√3sinx-cosx的值域为[-2,2].</p><p class="introTit">填空题</p><p>1、如图,在长方体ABCD-A<sub>1</sub>B<sub>1</sub>C<sub>1</sub>D<sub>1</sub>中,AB=1,AD=2,AA<sub>1</sub>=2,则二面角A-DD<sub>1</sub>-B的正切值为()
<img src="https://img2.meite.com/questions/202409/1366e3a1e9e4681.png" />
</p><p>答 案:<img src="https://img2.meite.com/questions/202409/1366e3aabede20b.png" /></p><p>解 析:易得<img src="https://img2.meite.com/questions/202409/1366e3aae9a9b6c.png" />,<img src="https://img2.meite.com/questions/202409/1366e3ab007062c.png" />平面角.在<img src="https://img2.meite.com/questions/202409/1366e3ab1ab51b8.png" />,AB=1AD=2,<img src="https://img2.meite.com/questions/202409/1366e3ab2d83821.png" />,∴二面角A-DD<sub>1</sub>-B的正切值为<img src="https://img2.meite.com/questions/202409/1366e3aabede20b.png" />.</p><p>2、<img src="https://img2.meite.com/questions/202409/1266e29a3e0507a.png" />=()</p><p>答 案:2</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1266e29a4563c46.png" /></p><p>3、函数<img src="https://img2.meite.com/questions/202409/1466e53d4dd18be.png" />的最小正周期是()</p><p>答 案:π</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1466e53d549721e.png" /><img src="https://img2.meite.com/questions/202409/1466e53d5b08234.png" /><img src="https://img2.meite.com/questions/202409/1466e53d600d7ea.png" /></p><p>4、<img src="https://img2.meite.com/questions/202409/1266e28fe1b5259.png" />展开式中的常数项为()
</p><p>答 案:<img src="https://img2.meite.com/questions/202409/1266e29459792a1.png" /></p><p>解 析:易知<img src="https://img2.meite.com/questions/202409/1266e28fe1b5259.png" />展开式的通项为<img src="https://img2.meite.com/questions/202409/1266e293f5bb2a2.png" />令12-3k =0,解得k=4,所以<img src="https://img2.meite.com/questions/202409/1266e28fe1b5259.png" />展开式中的常数项为<img src="https://img2.meite.com/questions/202409/1266e2942b3e608.png" /></p><p class="introTit">简答题</p><p>1、已知<img src="https://img2.meite.com/questions/202409/1266e2a116c4f74.png" />,该展开式的二项式系数之和为 32. (1)求n的值;(2)求<img src="https://img2.meite.com/questions/202409/1266e2a1279029b.png" />的值. </p><p>答 案:(1)因为<img src="https://img2.meite.com/questions/202409/1266e2a9e3ae8f8.png" />的展开式的二项式系数之和为 32, 所以2<sup>n</sup>=32,解得n=5.
(2)令x=1,得<img src="https://img2.meite.com/questions/202409/1266e2aa147b4a4.png" />
所以<img src="https://img2.meite.com/questions/202409/1266e2aa1f4438a.png" /></p><p>2、已知数列{an}是等差数列,a1=1,a3=3.
(1)求数列{an}的通项公式;
(2)设b<sub>n</sub>=(-1)<sup>n</sup>a<sub>n</sub>,数列{b<sub>n</sub>}的前n项和为T<sub>n</sub>,求T<sub>1</sub><sub>00</sub></p><p>答 案:<img src="https://img2.meite.com/questions/202409/1866ea3b778423a.png" /> <img src="https://img2.meite.com/questions/202409/1866ea3b80b8bb9.png" /></p>