2024年高职单招《数学(中职)》每日一练试题09月29日

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09/29
<p class="introTit">单选题</p><p>1、函数<img src="https://img2.meite.com/questions/202409/2166ee6d0ea9899.png" />的定义域是()  </p><ul><li>A:<img src='https://img2.meite.com/questions/202409/2166ee6d1ca9398.png' /></li><li>B:<img src='https://img2.meite.com/questions/202409/2166ee6d23cc4ec.png' /></li><li>C:<img src='https://img2.meite.com/questions/202409/2166ee6d2c4d124.png' /></li><li>D:<img src='https://img2.meite.com/questions/202409/2166ee6d33c218e.png' /></li></ul><p>答 案:B</p><p>解 析:因为<img src="https://img2.meite.com/questions/202409/2166ee705bb6a58.png" />,所以<img src="https://img2.meite.com/questions/202409/2166ee7063481ff.png" />,所以<img src="https://img2.meite.com/questions/202409/2166ee706a29d52.png" />,所以f(x)的定义域为<img src="https://img2.meite.com/questions/202409/2166ee6d23cc4ec.png" />。</p><p>2、若<img src="https://img2.meite.com/questions/202409/1366e3944e977b3.png" />,则x的值为()  </p><ul><li>A:3</li><li>B:6</li><li>C:9</li><li>D:3或6</li></ul><p>答 案:A</p><p>解 析:因为<img src="https://img2.meite.com/questions/202409/1366e394ab45e69.png" />,所以x+3+x=9,解得x=3.</p><p>3、已知平面直角坐标系上的两点A(-1,1),B(3,2),则<img src="https://img2.meite.com/questions/202409/2166ee786366f38.png" />=()</p><ul><li>A:√2</li><li>B:3</li><li>C:√6</li><li>D:√17</li></ul><p>答 案:D</p><p>解 析:由题意得<img src="https://img2.meite.com/questions/202409/2166ee786ce7e8c.png" /></p><p>4、已知集合M={0,1,2,3,4},N={3,4,5},则下列结论正确的是  </p><ul><li>A:<img src='https://img2.meite.com/questions/202409/0966de634faf0ac.png' /></li><li>B:<img src='https://img2.meite.com/questions/202409/0966de6356bb798.png' /></li><li>C:M∩N={3,4}</li><li>D:M∪N={0,1,2,5}</li></ul><p>答 案:C</p><p>解 析:因为M={0,1,2,3,4},N={3,4,5},所以M不包含N,N不包含M,M∩N={3,4},M∪N={0,1,2,3,4,5},故选C</p><p class="introTit">填空题</p><p>1、已知|a|=2,|b|=4,a·b=-4,则向量a与b的夹角为()  </p><p>答 案:5</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1966ebc583ea8e1.png" /><img src="https://img2.meite.com/questions/202409/1966ebc5d0ae256.png" /></p><p>2、若函数<img src="https://img2.meite.com/questions/202409/1266e29a85bbd26.png" />是对数函数,则a=()</p><p>答 案:5</p><p>解 析:<img src="https://img2.meite.com/questions/202409/1266e29a8d74883.png" /></p><p>3、已知球的直径为2,则该球的体积是()  </p><p>答 案:<img src="https://img2.meite.com/questions/202409/1866ea2dee84dd3.png" /></p><p>解 析:易得球的半径为1,故球的体积为<img src="https://img2.meite.com/questions/202409/1866ea2dfab0399.png" /></p><p>4、若(x-1)<sup>n</sup>的展开式中x<sup>2</sup>的系数是-10,则n的值为()  </p><p>答 案:5</p><p>解 析:因为(x-1)<sup>n</sup>的展开式中x<sup>2</sup>的系数是<img src="https://img2.meite.com/questions/202409/1266e2a816afaa9.png" />,所以n= 5.</p><p class="introTit">简答题</p><p>1、如图,正方体ABCD-A<sub>1</sub>B<sub>1</sub>C<sub>1</sub>D<sub>1</sub>的棱长为 2.(1)证明<img src="https://img2.meite.com/questions/202409/1366e3ec96a8814.png" /><br />(2)求 AD<sub>1</sub>与 BD 所成角的大小. <img src="https://img2.meite.com/questions/202409/1366e3e3f06edd3.png" />  </p><p>答 案:(1)在正方体ABCD-A<sub>1</sub>B<sub>1</sub>C<sub>1</sub>D<sub>1</sub>中,易得<img src="https://img2.meite.com/questions/202409/1366e3ff49f3077.png" /> 又<img src="https://img2.meite.com/questions/202409/1366e3ff57a3def.png" /> <img src="https://img2.meite.com/questions/202409/1366e3ff6d67c1a.png" /> ∵四边形 ABCD 是正方形, <img src="https://img2.meite.com/questions/202409/1366e3ff91d4291.png" /> 又<img src="https://img2.meite.com/questions/202409/1366e3ffa619eac.png" /> <img src="https://img2.meite.com/questions/202409/1366e3ffb57d486.png" /> 又<img src="https://img2.meite.com/questions/202409/1366e3ffc59fc60.png" /> <img src="https://img2.meite.com/questions/202409/1366e3ffcf63532.png" /> (2)在正方体ABCD-A<sub>1</sub>B<sub>1</sub>C<sub>1</sub>D<sub>1</sub>中,易得A<sub>1</sub>D<sub>1</sub>// BC, ∴<img src="https://img2.meite.com/questions/202409/1366e400089b44e.png" />即AD<sub>1</sub>与BD所成的角, 易知C<sub>1</sub>B=BD=C<sub>1</sub>D=<img src="https://img2.meite.com/questions/202409/1366e40027975ed.png" /> ∴<img src="https://img2.meite.com/questions/202409/1366e40038aa3af.png" />为等边三角形, <img src="https://img2.meite.com/questions/202409/1366e4003f7c51c.png" /> ∴AD<sub>1</sub>与BD所成的角为<img src="https://img2.meite.com/questions/202409/1366e4005d07407.png" />  </p><p>2、已知等差数列{a<sub>n</sub>}的前n项和为S<sub>n</sub>且S<sub>7</sub>=28,S<sub>15</sub>=120 (1)求数列{an}的首项a<sub>1</sub>和公差d; (2)证明数列<img src="https://img2.meite.com/questions/202409/1866ea728ca150a.png" /> 是等差数列,并求出<img src="https://img2.meite.com/questions/202409/1866ea7294997a6.png" />的前n项和T<sub>n</sub></p><p>答 案:<img src="https://img2.meite.com/questions/202409/1866ea729e7f2f4.png" /><img src="https://img2.meite.com/questions/202409/1866ea72a338d55.png" /> <img src="https://img2.meite.com/questions/202409/1866ea72a832b55.png" /><img src="https://img2.meite.com/questions/202409/1866ea72b4c64a8.png" /><img src="https://img2.meite.com/questions/202409/1866ea72b9d112a.png" /><img src="https://img2.meite.com/questions/202409/1866ea72c0c897c.png" /><img src="https://img2.meite.com/questions/202409/1866ea72c76d47a.png" /><img src="https://img2.meite.com/questions/202409/1866ea72ce267db.png" /></p>
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