2024年成考高起点《数学(理)》每日一练试题08月21日
<p class="introTit">单选题</p><p>1、函数f(x)=x<sup>3</sup>-6x<sup>2</sup>+9x-3的单调区间为()。</p><ul><li>A:(-∞,-3)、(-3,1)、(1,+∞)</li><li>B:(-∞,-1)、(-1,3)、(3,+∞)</li><li>C:(-∞,1)、(1,3)、(3,+∞)</li><li>D:(-∞,-3)、(-3,-1)、(-1,+∞)</li></ul><p>答 案:C</p><p>解 析:y=x<sup>3</sup>-6x<sup>2</sup>+9x-3则y’=3x<sup>2</sup>+12x+9 令y’=0,x<sup>2</sup>-4x+3=0<img src="https://img2.meite.com/questions/202408/1666bf067acf250.png" />(x-1)(x-3)=0解得,x1=1,x2=3 四个答案中,只有C具有1、3两个极值点,其余3个没有,故应选C。
</p><p>2、函数<img src="https://img2.meite.com/questions/202303/15641164b43c663.png" />的反函数是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/15641164d78e1fc.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/15641164de92884.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/15641164e5206d4.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/15641164e93e32e.png' /></li></ul><p>答 案:A</p><p>解 析:<img src="https://img2.meite.com/questions/202303/15641168660282b.png" />,由于x≤0,故<img src="https://img2.meite.com/questions/202303/1564116881a60a4.png" />把x与y互换,得所求反函数为<img src="https://img2.meite.com/questions/202303/15641168ab18774.png" /></p><p>3、过A<img src="https://img2.meite.com/questions/202408/1966c2b9a6da300.png" />B(-5,0)两点直线的倾斜角为()。</p><ul><li>A:<img src='https://img2.meite.com/questions/202408/1966c2b9aa76f40.png' /></li><li>B:<img src='https://img2.meite.com/questions/202408/1966c2b9aec98ec.png' /></li><li>C:<img src='https://img2.meite.com/questions/202408/1966c2b9b168c67.png' /></li><li>D:<img src='https://img2.meite.com/questions/202408/1966c2b9b52cefc.png' /></li></ul><p>答 案:C</p><p>解 析:<img src="https://img2.meite.com/questions/202408/1966c2b9b91d75c.png" /></p><p>4、已知<img src="https://img2.meite.com/questions/202303/15641164fa2237c.png" />,则sin2α=()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/1564116517f1106.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/156411651ce8f2e.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/15641165224b184.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/1564116525c6916.png' /></li></ul><p>答 案:D</p><p>解 析:<img src="https://img2.meite.com/questions/202303/1564116928359d5.png" />两边平方得<img src="https://img2.meite.com/questions/202303/156411693780841.png" />,故<img src="https://img2.meite.com/questions/202303/156411694945042.png" /></p><p class="introTit">主观题</p><p>1、设a为实数,且tanα和tanβ是方程ax<sup>2</sup>+(2a-3)x+(a-2)=0的两个实根,求tan(α+β)的最小值。</p><p>答 案:由已知得<img src="https://img2.meite.com/questions/202408/1666bef0e318894.png" /><img src="https://img2.meite.com/questions/202408/1666bef0e531f77.png" /></p><p>2、某工厂每月生产x台游戏机的收入为R(x)=<img src="https://img2.meite.com/questions/202303/28642259676bd4d.png" />+130x-206(百元),成本函数为C(x)=50x+100(百元),当每月生产多少台时,获利润最大?最大利润为多少?
</p><p>答 案:利润 =收入-成本, L(x)=R(x)-C(x)=<img src="https://img2.meite.com/questions/202303/28642259c06a284.png" />+130x-206-(50x+100)=<img src="https://img2.meite.com/questions/202303/28642259e2077b7.png" />+80x-306
法一:用二次函数<img src="https://img2.meite.com/questions/202303/28642259fb36916.png" />当a<0时有最大值
<img src="https://img2.meite.com/questions/202303/2864225a14ed5aa.png" />是开口向下的抛物线,有最大值
<img src="https://img2.meite.com/questions/202303/2864225a2c75330.png" />
法二:用导数来求解
<img src="https://img2.meite.com/questions/202303/2864225a43988b8.png" />
因为x=90是函数在定义域内唯一驻点
所以x=90是函数的极大值点,也是函数的最大值点,其最大值为L(90)=3294
</p><p>3、记△ABC的内角A,B,C的对边分别为a,b,c,已知B=60°,b<sup>2</sup>=ac,求A。
</p><p>答 案:由余弦定理b<sup>2</sup>=a<sup>2</sup>+c<sup>2</sup>-2accosB,可得ac=a<sup>2</sup>+c<sup>2</sup>-ac,即a<sup>2</sup>+c<sup>2</sup>-2ac=(a-c)<sup>2</sup>=0,解得a=c。
又因为B=60°,故△ABC为等边三角形,所以A=60°</p><p>4、求(1+tan10°)(1+tan35°)的值。
</p><p>答 案:原式=1+tan10°+tan35°+tan10°·tan35°<img src="https://img2.meite.com/questions/202408/1666bf080f0f9d3.png" /></p><p class="introTit">填空题</p><p>1、函数<img src="https://img2.meite.com/questions/202303/2864225857f0d64.png" />的图像与坐标轴的交点共有()
</p><p>答 案:2</p><p>解 析:当x=0时,y=<img src="https://img2.meite.com/questions/202303/286422587f2a68b.png" />-2=-1,故函数与y轴交于(0,-1)点,令y=0,则有<img src="https://img2.meite.com/questions/202303/28642258b372965.png" />故函数与x轴交于(1,0) 点,因此函数 <img src="https://img2.meite.com/questions/202303/28642258c6c51c8.png" />与坐标轴的交点共有 2个.</p><p>2、若平面向量a=(x,1),b=(1,-2),且a//b,则x=()
</p><p>答 案:<img src="https://img2.meite.com/questions/202303/286422508f0554f.png" /></p><p>解 析:由于a//b,故<img src="https://img2.meite.com/questions/202303/286422509cd5c14.png" /></p>