2024年成考高起点《数学(文史)》每日一练试题08月05日

<p class="introTit">单选题</p><p>1、已知函数f(x)的定义域为R，且满足f(2x)=<img src="https://img2.meite.com/questions/202303/296423a4f003da6.png" />,则f(x)的反函数为（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/296423a506c2ca4.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/296423a50aa8fc5.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/296423a51284df7.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/296423a516a6101.png' /></li></ul><p>答 案：B</p><p>解 析：令2x=t，则x=<img src="https://img2.meite.com/questions/202303/296423a5d090a18.png" /> <img src="https://img2.meite.com/questions/202303/296423a5d7d5daa.png" />  </p><p>2、函数<img src="https://img2.meite.com/questions/202303/14641028ec3037a.png" />的图像与直线y=4的交点坐标为（）</p><ul><li>A：(0,4)</li><li>B：(4,64)</li><li>C：(1,4)</li><li>D：(4,16)</li></ul><p>答 案：C</p><p>解 析：令y=4^x=4，解得x=1，故所求交点为（1,4).</p><p>3、已知<img src="https://img2.meite.com/questions/202303/14641027b0e9511.png" />，则sin2α=（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/14641027d7193ea.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/14641027dcded6f.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/14641027e2be0ff.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/14641027e75615d.png' /></li></ul><p>答 案：D</p><p>解 析：<img src="https://img2.meite.com/questions/202303/1464102b8ba4635.png" />两边平方得<img src="https://img2.meite.com/questions/202303/1464102bb0eb6cc.png" /><img src="https://img2.meite.com/questions/202303/1464102bb4c5429.png" />，故<img src="https://img2.meite.com/questions/202303/1464102bc8067d1.png" /></p><p>4、不等式|2x-3|≤1的解集为（）</p><ul><li>A：{x|1≤x≤2}</li><li>B：{x|x≤-1或x≥2}</li><li>C：{x|1≤x≤3}</li><li>D：{x|2≤x≤3}</li></ul><p>答 案：A</p><p>解 析：<img src="https://img2.meite.com/questions/202303/2964239aeb5ea0d.png" /><img src="https://img2.meite.com/questions/202303/2964239afad8c35.png" />故原不等式的解集为{x|1≤x≤2}</p><p class="introTit">主观题</p><p>1、已知等差数列<img src="https://img2.meite.com/questions/202303/296423eaf9717d6.png" />前n项和<img src="https://img2.meite.com/questions/202303/296423eb032d219.png" /> （Ⅰ）求通项<img src="https://img2.meite.com/questions/202303/296423eb1a4ebf5.png" />的表达式 （Ⅱ）求<img src="https://img2.meite.com/questions/202303/296423eb26c2214.png" />的值  </p><p>答 案：（Ⅰ）当n=1时，由<img src="https://img2.meite.com/questions/202303/296423eb432a645.png" />得<img src="https://img2.meite.com/questions/202303/296423eb5068b03.png" /> <img src="https://img2.meite.com/questions/202303/296423eb59a45cd.png" /> <img src="https://img2.meite.com/questions/202303/296423eb6100c03.png" /> 也满足上式，故<img src="https://img2.meite.com/questions/202303/296423eb755b7df.png" />=1-4n（n≥1） （Ⅱ）由于数列<img src="https://img2.meite.com/questions/202303/296423eb93e2df0.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423eba5a3367.png" />公差为d=-4的等差数列，所以<img src="https://img2.meite.com/questions/202303/296423ebc29c045.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423ebe5ba947.png" />公差为d=-8，项数为13的等差数列，于是由等差数列前n项和公式得： <img src="https://img2.meite.com/questions/202303/296423ec1ac9811.png" /><img src="https://img2.meite.com/questions/202303/296423ec20a013e.png" />  </p><p>2、在△ABC中，B=120°,C=30°,BC=4，求△ABC的面积．</p><p>答 案：因为A= 180°-B-C=30°，所以AB = BC=4.因此△ABC的面积<img src="https://img2.meite.com/questions/202303/1564111c8c97743.png" /></p><p>3、已知函数f（x）=（x-4）（x2-a）。（I）求f’（x）；<br />（Ⅱ）若f’（-1）=8，求f（x）在区间[0，4]的最大值与最小值。</p><p>答 案：(I)f'(x) =(x-4)'(x²-a)+(x-4)(x²-a)’ =x²-a+2x(x-4) =3x²-8x-a. (Ⅱ)由于f’(-1)=3+8-a=8,得a=3. 令f'(x)=3x²-8x-3=0,解得x1=3，<img src="https://img2.meite.com/questions/202404/2066238195d9945.png" />（舍去）又f（0）=12，f（3）=-6，f（4）=0所以在区间[0，4]上函数最大值为12，最小值为-6</p><p>4、已知抛物线C：y2=2px（p>0）的焦点到准线的距离为1。（I）求C的方程；<br />（Ⅱ）若A（1，m）（m>0）为C上一点，O为坐标原点，求C上另一点B的坐标，使得OA⊥OB。</p><p>答 案：(I)由题意,该抛物线的焦点到准线的距离为<img src="https://img2.meite.com/questions/202404/20662381634105d.png" /> 所以抛物线C的方程为y²=2x. (Ⅱ)因A(l,m)(m>0)为C上一点,故有m²=2, 可得 m=<img src="https://img2.meite.com/questions/202404/206623816da9881.png" />因此A点坐标为<img src="https://img2.meite.com/questions/202404/20662381732cfb3.png" /> 设B点坐标为<img src="https://img2.meite.com/questions/202404/2066238179d51e4.png" /><img src="https://img2.meite.com/questions/202404/20662381806c6f7.png" /><img src="https://img2.meite.com/questions/202404/2066238187c9047.png" /></p><p class="introTit">填空题</p><p>1、设<img src="https://img2.meite.com/questions/202303/2964239c3b4ac2f.png" />则<img src="https://img2.meite.com/questions/202303/2964239c42d80d7.png" /></p><p>答 案：-1</p><p>解 析：<img src="https://img2.meite.com/questions/202303/2964239ca8a1cc9.png" /> <img src="https://img2.meite.com/questions/202303/2964239cb367f80.png" /> <img src="https://img2.meite.com/questions/202303/2964239cc4f078f.png" />  </p><p>2、函数y=-x²+ax图像的对称轴为x=2，则a=______。</p><p>答 案：4  </p><p>解 析：本题主要考查的知识点为二次函数的性质。 由题意，该函数图像的对称轴为<img src="https://img2.meite.com/questions/202404/20662381471af77.png" />得a=4。</p>