2024年成考高起点《数学(文史)》每日一练试题07月17日
<p class="introTit">单选题</p><p>1、已知向量a=(3,4),b=(0,-2),则cos=()
</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/296423b170c2f95.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/296423b17508b91.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/296423b17967146.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/296423b17e2de84.png' /></li></ul><p>答 案:B</p><p>解 析:因为a=(3,4),b=(0,-2), <img src="https://img2.meite.com/questions/202303/296423b1f8241e7.png" />
</p><p>2、已知直线l:3x一2y-5=0,圆C:<img src="https://img2.meite.com/questions/202303/146410290217fd9.png" />,则C上到l的距离为1的点共有()</p><ul><li>A:1个</li><li>B:2个</li><li>C:3个</li><li>D:4个</li></ul><p>答 案:D</p><p>解 析:由题可知圆的圆心为(1.-1),半径为2,圆心到直线的距离为<img src="https://img2.meite.com/questions/202303/1464102c5f67c9b.png" />,即直线过圆心,因此圆C上到直线的距离为1的点共有4个.</p><p>3、函数<img src="https://img2.meite.com/questions/202303/296423e9f4c42ba.png" />与y<img src="https://img2.meite.com/questions/202303/296423e9fce2f9b.png" />的图像之间的关系是
</p><ul><li>A:关于原点对称</li><li>B:关于x轴对称</li><li>C:关于直线 y=1对称</li><li>D:关于y轴对称</li></ul><p>答 案:D</p><p>解 析:<img src="https://img2.meite.com/questions/202303/296423ea4eab0e4.png" /><img src="https://img2.meite.com/questions/202303/296423ea5d59f26.png" />关于y轴对称,</p><p>4、一批产品共有5件,其中4件为正品,1件为次品,从中一次取出2件均为正品的概率为()。</p><ul><li>A:0.6</li><li>B:0.5</li><li>C:0.4</li><li>D:0.3</li></ul><p>答 案:A</p><p>解 析:本题主要考查的知识点为随机事件的概率。 一次取出2件均为正品的概率为<img src="https://img2.meite.com/questions/202404/2066237f1e565aa.png" /></p><p class="introTit">主观题</p><p>1、在△ABC中,AB=2,BC=3,B=60°,求AC及△ABC的面积</p><p>答 案:<img src="https://img2.meite.com/questions/202303/296423a37bd555e.png" /></p><p>2、在△ABC中,B=120°,C=30°,BC=4,求△ABC的面积.</p><p>答 案:因为A= 180°-B-C=30°,所以AB = BC=4.因此△ABC的面积<img src="https://img2.meite.com/questions/202303/1564111c8c97743.png" /></p><p>3、已知等差数列<img src="https://img2.meite.com/questions/202303/296423eaf9717d6.png" />前n项和<img src="https://img2.meite.com/questions/202303/296423eb032d219.png" />
(Ⅰ)求通项<img src="https://img2.meite.com/questions/202303/296423eb1a4ebf5.png" />的表达式
(Ⅱ)求<img src="https://img2.meite.com/questions/202303/296423eb26c2214.png" />的值
</p><p>答 案:(Ⅰ)当n=1时,由<img src="https://img2.meite.com/questions/202303/296423eb432a645.png" />得<img src="https://img2.meite.com/questions/202303/296423eb5068b03.png" /> <img src="https://img2.meite.com/questions/202303/296423eb59a45cd.png" />
<img src="https://img2.meite.com/questions/202303/296423eb6100c03.png" />
也满足上式,故<img src="https://img2.meite.com/questions/202303/296423eb755b7df.png" />=1-4n(n≥1)
(Ⅱ)由于数列<img src="https://img2.meite.com/questions/202303/296423eb93e2df0.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423eba5a3367.png" />公差为d=-4的等差数列,所以<img src="https://img2.meite.com/questions/202303/296423ebc29c045.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423ebe5ba947.png" />公差为d=-8,项数为13的等差数列,于是由等差数列前n项和公式得:
<img src="https://img2.meite.com/questions/202303/296423ec1ac9811.png" /><img src="https://img2.meite.com/questions/202303/296423ec20a013e.png" />
</p><p>4、设函数f(x)<img src="https://img2.meite.com/questions/202303/296423a66bbdb95.png" />且f'(-1)=-36
(Ⅰ)求m
(Ⅱ)求f(x)的单调区间</p><p>答 案:(Ⅰ)由已知得f'=<img src="https://img2.meite.com/questions/202303/296423a74f41b7f.png" /> 又由f'(-1)=-36得
6-6m-36=-36
故m=1.
(Ⅱ)由(Ⅰ)得f'(x)=<img src="https://img2.meite.com/questions/202303/296423a792d1aff.png" />
令f'(x)=0,解得<img src="https://img2.meite.com/questions/202303/296423a7b14cf3f.png" />
当x<-3时,f'(x)>0;
当-3<x<2时,f'(x)<0;
当x>2时,f'(x)>0;
故f(x)的单调递减区间为(-3,2),f(x)的单调递增区间为(-∞,-3),(2,+∞)
</p><p class="introTit">填空题</p><p>1、曲线在点(1,1)处的切线方程是______。
</p><p>答 案:2x+y-3=0
</p><p>解 析:本题主要考查的知识点为切线方程。
由题意,该切线斜率<img src="https://img2.meite.com/questions/202404/206623813f54152.png" />,又过点(1,1),所以切线方程为y-1=-2(x-1),即2x+y-3=0。</p><p>2、函数y=<img src="https://img2.meite.com/questions/202303/296423a650306d1.png" />的定义域是()</p><p>答 案:[1,+∞)</p><p>解 析:要是函数y=<img src="https://img2.meite.com/questions/202303/296423a6e097a67.png" />有意义,需使<img src="https://img2.meite.com/questions/202303/296423a6f397863.png" /><img src="https://img2.meite.com/questions/202303/296423a703abb7f.png" /> 所以函数的定义域为{x|x≥1}=[1,+∞)
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