2024年成考高起点《数学(理)》每日一练试题05月13日
<p class="introTit">单选题</p><p>1、函数<img src="https://img2.meite.com/questions/202303/15641164b43c663.png" />的反函数是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/15641164d78e1fc.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/15641164de92884.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/15641164e5206d4.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/15641164e93e32e.png' /></li></ul><p>答 案:A</p><p>解 析:<img src="https://img2.meite.com/questions/202303/15641168660282b.png" />,由于x≤0,故<img src="https://img2.meite.com/questions/202303/1564116881a60a4.png" />把x与y互换,得所求反函数为<img src="https://img2.meite.com/questions/202303/15641168ab18774.png" /></p><p>2、圆<img src="https://img2.meite.com/questions/202303/286422577705f47.png" />的圆心在()点上
</p><ul><li>A:(1,-2)</li><li>B:(0,5)</li><li>C:(5,5)</li><li>D:(0,0)</li></ul><p>答 案:A</p><p>解 析:因为<img src="https://img2.meite.com/questions/202303/2864225806cc8be.png" />所以圆的圆心为O(1,-2)</p><p>3、对满足a>b的任意两个非零实数,下列不等式成立的是()
</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/2864228b1f8efca.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/2864228b2567c86.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/2864228b2a86110.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/2864228b30e50d4.png' /></li></ul><p>答 案:D</p><p>解 析:A错误,例如-2>4,而<img src="https://img2.meite.com/questions/202303/2864228ba68a732.png" /> B错误,例如:-10>100,而<img src="https://img2.meite.com/questions/202303/2864228bbe163a2.png" />
C错误,例如:-1>-2,而<img src="https://img2.meite.com/questions/202303/2864228bd9de925.png" />
<img src="https://img2.meite.com/questions/202303/2864228be175c60.png" /></p><p>4、方程<img src="https://img2.meite.com/questions/202303/286422844e41cfc.png" />的图像是下图中的()
</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/286422845f870bc.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/2864228467a7899.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/286422847066eef.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/286422847761b5b.png' /></li></ul><p>答 案:D</p><p>解 析:本题属于读图题型,在寻求答案时,要着重讨论方程的表达式 <img src="https://img2.meite.com/questions/202303/28642284efc983b.png" />
<img src="https://img2.meite.com/questions/202303/286422851faebf4.png" />
<img src="https://img2.meite.com/questions/202303/2864228526ccc03.png" />
</p><p class="introTit">主观题</p><p>1、为了测河的宽,在岸边选定两点A和B,望对岸标记物C,测得<img src="https://img2.meite.com/questions/202303/2864228db8c0e49.png" />AB=120m,求河的宽
<img src="https://img2.meite.com/questions/202303/2864228dd64bdcb.png" /></p><p>答 案:如图, <img src="https://img2.meite.com/questions/202303/2864228df3f06d3.png" />
∵∠C=180°-30°-75°=75°
∴△ABC为等腰三角形,则AC=AB=120m
过C做CD⊥AB,则由Rt△ACD可求得CD=<img src="https://img2.meite.com/questions/202303/2864228e8a387f3.png" />=60m,
即河宽为60m
</p><p>2、建筑一个容积为8000<img src="https://img2.meite.com/questions/202303/2864224b406cbf6.png" />,深为6m的长方体蓄水池,池壁每<img src="https://img2.meite.com/questions/202303/2864224b5cac16d.png" />的造价为15元,池底每<img src="https://img2.meite.com/questions/202303/2864224b60ac28e.png" />的造价为30元。(I)把总造价y(元)表示为长x(m)的函数;(Ⅱ)求函数的定义域
</p><p>答 案:<img src="https://img2.meite.com/questions/202303/2864224be4311f4.png" /><img src="https://img2.meite.com/questions/202303/2864224bee67713.png" /></p><p>3、设函数f(x)=xlnx+x.(I)求曲线y=f(x)在点((1,f(1))处的切线方程;<br />(II)求f(x)的极值.</p><p>答 案:(I)f(1)=1,f'(x)=2+lnx,故f'(1)=2.所以曲线y=f(x)在点(1,f(1))处的切线方程为y=2x-1.(II)令f'(x)=0,解得<img src="https://img2.meite.com/questions/202303/1564116d2d14a94.png" />当<img src="https://img2.meite.com/questions/202303/1564116d3d33026.png" />时,f'(x)<O;当<img src="https://img2.meite.com/questions/202303/1564116d6f6aec3.png" />时,f'(x)>O.故f(x)在区间<img src="https://img2.meite.com/questions/202303/1564116db9a0764.png" />单调递减,在区间<img src="https://img2.meite.com/questions/202303/1564116dc99fc91.png" />单调递增.因此f(x)在<img src="https://img2.meite.com/questions/202303/1564116ddb842d0.png" />时取得极小值<img src="https://img2.meite.com/questions/202303/1564116de4f1b79.png" /></p><p>4、在正四棱柱ABCD-A'B'C'D'中,<img src="https://img2.meite.com/questions/202303/2864229a3bc3098.png" />
(Ⅰ)写出向量<img src="https://img2.meite.com/questions/202303/2864229a57ba174.png" />和<img src="https://img2.meite.com/questions/202303/2864229a5e46ac8.png" />关于基底{a,b,c}的分解式;
(Ⅱ)求证:<img src="https://img2.meite.com/questions/202303/2864229a76ba56d.png" />
(Ⅲ)求证:<img src="https://img2.meite.com/questions/202303/2864229a7fdd541.png" />
</p><p>答 案:(Ⅰ)由题意知(如图所示) <img src="https://img2.meite.com/questions/202303/2864229af6b1567.png" />
<img src="https://img2.meite.com/questions/202303/2864229afe90f50.png" />
<img src="https://img2.meite.com/questions/202303/2864229b08314c5.png" />
</p><p class="introTit">填空题</p><p>1、九个学生期末考试的成绩分别为79 63 88 94 99 77 89 81 85这九个学生成绩的中位数为______。
</p><p>答 案:85
</p><p>解 析:本题主要考查的知识点为中位数. 将成绩按由小到大排列:63,77,79,81,85,88,89,94,99.因此中位数为85。</p><p>2、lg(tan43°tan45°tan47°)=()
</p><p>答 案:0</p><p>解 析:lg(tan43°tan45°tan47°)=lg(tan43°tan45°cot43°)=lgtan45°=lg1=0</p>