2024年成考高起点《数学(文史)》每日一练试题04月14日

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04/14
<p class="introTit">单选题</p><p>1、任选一个两位数,它恰好是10的倍数的概率是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/2964239a9b1203b.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/2964239a9f21f1c.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/2964239aa80509d.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/2964239aa374c5f.png' /></li></ul><p>答 案:C</p><p>解 析:由已知条件可知此题属于等可能事件.两位数(正整数)从10~99共有90个,则n=90,是10的倍数的两位数共有9个,则m=9,<img src="https://img2.meite.com/questions/202303/2964239b50cf34a.png" />故任选一个两位数(正整数),它恰好是10的倍数的概率是<img src="https://img2.meite.com/questions/202303/2964239b6932ff5.png" /></p><p>2、从15名学生中选出两人担任正、副班长,不同的选举结果共有()  </p><ul><li>A:30种</li><li>B:90种</li><li>C:210种</li><li>D:225种</li></ul><p>答 案:C</p><p>解 析:由已知条件可知本题属于排列问题,<img src="https://img2.meite.com/questions/202303/296423b1cca0339.png" /></p><p>3、已知向量i,j为互相垂直的单位向量,向量a=2i+mj,若|a|=2,则m=()</p><ul><li>A:-2</li><li>B:-1</li><li>C:0</li><li>D:1</li></ul><p>答 案:C</p><p>解 析:由题可知a=(2,m),因此<img src="https://img2.meite.com/questions/202303/1464102be29a7c0.png" />,故m=0.</p><p>4、某学校为新生开设了4门选修课程,规定每位新生至少要选其中3门,则一位新生不同的选课方案共有 ( )</p><ul><li>A:7种</li><li>B:4种</li><li>C:5种</li><li>D:6种</li></ul><p>答 案:C</p><p class="introTit">主观题</p><p>1、已知等差数列<img src="https://img2.meite.com/questions/202303/296423eaf9717d6.png" />前n项和<img src="https://img2.meite.com/questions/202303/296423eb032d219.png" /> (Ⅰ)求通项<img src="https://img2.meite.com/questions/202303/296423eb1a4ebf5.png" />的表达式 (Ⅱ)求<img src="https://img2.meite.com/questions/202303/296423eb26c2214.png" />的值  </p><p>答 案:(Ⅰ)当n=1时,由<img src="https://img2.meite.com/questions/202303/296423eb432a645.png" />得<img src="https://img2.meite.com/questions/202303/296423eb5068b03.png" /> <img src="https://img2.meite.com/questions/202303/296423eb59a45cd.png" /> <img src="https://img2.meite.com/questions/202303/296423eb6100c03.png" /> 也满足上式,故<img src="https://img2.meite.com/questions/202303/296423eb755b7df.png" />=1-4n(n≥1) (Ⅱ)由于数列<img src="https://img2.meite.com/questions/202303/296423eb93e2df0.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423eba5a3367.png" />公差为d=-4的等差数列,所以<img src="https://img2.meite.com/questions/202303/296423ebc29c045.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423ebe5ba947.png" />公差为d=-8,项数为13的等差数列,于是由等差数列前n项和公式得: <img src="https://img2.meite.com/questions/202303/296423ec1ac9811.png" /><img src="https://img2.meite.com/questions/202303/296423ec20a013e.png" />  </p><p>2、设函数f(x)<img src="https://img2.meite.com/questions/202303/296423a66bbdb95.png" />且f'(-1)=-36 (Ⅰ)求m (Ⅱ)求f(x)的单调区间</p><p>答 案:(Ⅰ)由已知得f'=<img src="https://img2.meite.com/questions/202303/296423a74f41b7f.png" /> 又由f'(-1)=-36得 6-6m-36=-36 故m=1. (Ⅱ)由(Ⅰ)得f'(x)=<img src="https://img2.meite.com/questions/202303/296423a792d1aff.png" /> 令f'(x)=0,解得<img src="https://img2.meite.com/questions/202303/296423a7b14cf3f.png" /> 当x<-3时,f'(x)>0; 当-3<x<2时,f'(x)<0; 当x>2时,f'(x)>0; 故f(x)的单调递减区间为(-3,2),f(x)的单调递增区间为(-∞,-3),(2,+∞)  </p><p>3、在△ABC中,B=120°,C=30°,BC=4,求△ABC的面积.</p><p>答 案:因为A= 180°-B-C=30°,所以AB = BC=4.因此△ABC的面积<img src="https://img2.meite.com/questions/202303/1564111c8c97743.png" /></p><p>4、已知三角形的一个内角是<img src="https://img2.meite.com/questions/202303/296423b4bf816f0.png" />,面积是<img src="https://img2.meite.com/questions/202303/296423b4cd02d83.png" />周长是20,求各边的长.  </p><p>答 案:设三角形三边分别为a,b,c,∠A=60°, <img src="https://img2.meite.com/questions/202303/296423b55f6ab61.png" />  </p><p class="introTit">填空题</p><p>1、设<img src="https://img2.meite.com/questions/202303/2964239c3b4ac2f.png" />则<img src="https://img2.meite.com/questions/202303/2964239c42d80d7.png" /></p><p>答 案:-1</p><p>解 析:<img src="https://img2.meite.com/questions/202303/2964239ca8a1cc9.png" /> <img src="https://img2.meite.com/questions/202303/2964239cb367f80.png" /> <img src="https://img2.meite.com/questions/202303/2964239cc4f078f.png" />  </p><p>2、函数f(x)=<img src="https://img2.meite.com/questions/202303/296423b497a799f.png" />在区间[-3,3]上的最大值为()  </p><p>答 案:4</p><p>解 析:这题考的是高次函数的最值问题,可用导数来求函数在区间[-3,3]上的最值。<img src="https://img2.meite.com/questions/202303/296423b5082e922.png" /> 列出表格<img src="https://img2.meite.com/questions/202303/296423b517619c0.png" /> 由上表可知函数在[-3,3]上,在x=1点处有最大值为4.  </p>
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