2024年成考专升本《高等数学二》每日一练试题04月12日
<p class="introTit">判断题</p><p>1、若<img src="https://img2.meite.com/questions/202307/1364af5780970e6.png" />,则<img src="https://img2.meite.com/questions/202307/1364af578624075.png" />。()
</p><p>答 案:错</p><p>解 析:<img src="https://img2.meite.com/questions/202212/06638ef8852e1bd.png" />所以<img src="https://img2.meite.com/questions/202212/06638ef88b66bc1.png" /> </p><p class="introTit">单选题</p><p>1、下列等式中成立的是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202212/0763902c0a65152.png' /></li><li>B:<img src='https://img2.meite.com/questions/202212/0763902c15e917b.png' /></li><li>C:<img src='https://img2.meite.com/questions/202212/0763902c26761a1.png' /></li><li>D:<img src='https://img2.meite.com/questions/202212/0763902c31733ef.png' /></li></ul><p>答 案:D</p><p>解 析:AD两项,<img src="https://img2.meite.com/questions/202212/0763902c3d17d53.png" />;BC两项,<img src="https://img2.meite.com/questions/202212/0763902c4e157a0.png" /></p><p>2、二元函数<img src="https://img2.meite.com/questions/202212/076390504603e1b.png" />的定义域为().</p><ul><li>A:1≤x<sup>2</sup>+y<sup>2</sup>≤4</li><li>B:1<x<sup>2</sup>+y<sup>2</sup>≤4</li><li>C:1≤x<sup>2</sup>+y<sup>2</sup><4</li><li>D:1<x<sup>2</sup>+y<sup>2</sup><4</li></ul><p>答 案:B</p><p>解 析:对数的真数部分大于0,即x<sup>2</sup>+y<sup>2</sup>-1>0;根号内大于等于0,即4-x<sup>2</sup>-y<sup>2</sup>≥0.</p><p class="introTit">主观题</p><p>1、加工某零件需经两道工序,若每道工序的次品率分别为0.02与0.03,加工的工序互不影响,求此加工的零件是次品的概率.</p><p>答 案:解:A={第一道工序是次品),B={第二道工序是次品),C={产品是次品},则C=A+B且A与B相互独立,P(C)=P(A+B)=P(A)+P(B)-P(AB)=P(A)+P(B)-P(A)·P(B)=0.02+0.03-0.02×0.03=0.0494.</p><p>2、计算<img src="https://img2.meite.com/questions/202212/03638b0fe931138.png" /></p><p>答 案:解:此处为<img src="https://img2.meite.com/questions/202212/03638b100735583.png" />型极限,可使用洛必达法则<img src="https://img2.meite.com/questions/202212/03638b101630e34.png" /></p><p class="introTit">填空题</p><p>1、设函数<img src="https://img2.meite.com/questions/202212/07638fec6e8db94.png" />,且f(u)可导,则dy=().</p><p>答 案:<img src="https://img2.meite.com/questions/202212/07638fec8829d71.png" /></p><p>解 析:因为<img src="https://img2.meite.com/questions/202212/07638fec9aa2838.png" />,所以<img src="https://img2.meite.com/questions/202212/07638feca9ab2d8.png" /></p><p>2、设函数<img src="https://img2.meite.com/questions/202303/076406d7a736088.png" />,则<img src="https://img2.meite.com/questions/202303/076406d7b8362e6.png" />()
</p><p>答 案:<img src="https://img2.meite.com/questions/202303/076406e1c147ee5.png" /></p><p>解 析:由题可得<img src="https://img2.meite.com/questions/202303/076406e1ce7b214.png" />因此<img src="https://img2.meite.com/questions/202303/076406e1d8ed505.png" /></p><p class="introTit">简答题</p><p>1、计算<img src="https://img2.meite.com/questions/202204/256266681e38a4b.png" /></p><p>答 案:<img src="https://img2.meite.com/questions/202204/2562666955ecf07.png" /><img src="https://img2.meite.com/questions/202204/256266696a949be.png" /></p><p>2、求极限<img src="https://img2.meite.com/questions/202303/2164194ca2a724d.png" />
</p><p>答 案:原式=<img src="https://img2.meite.com/questions/202303/2164194cb6a43a7.png" /></p>