2024年成考高起点《数学(理)》每日一练试题04月06日

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04/06
<p class="introTit">单选题</p><p>1、<img src="https://img2.meite.com/questions/202303/2864225b891ad2c.png" />展开式中,末3项的系数(a,x 均未知) 之和为()  </p><ul><li>A:22</li><li>B:12</li><li>C:10</li><li>D:-10</li></ul><p>答 案:C</p><p>解 析:<img src="https://img2.meite.com/questions/202303/2864225bbb4b976.png" /><img src="https://img2.meite.com/questions/202303/2864225bc299c02.png" /><img src="https://img2.meite.com/questions/202303/2864225bcaa8096.png" />末三项数之和为<img src="https://img2.meite.com/questions/202303/2864225bdfc7788.png" /><img src="https://img2.meite.com/questions/202303/2864225beaa0cc1.png" /></p><p>2、下列函数中,为减函数的是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/1564116457c8a2d.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/156411645ea88b7.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/1564116464062a5.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/1564116467a737e.png' /></li></ul><p>答 案:C</p><p>解 析:由对数函数的性质可知,当底数大于0小于1时,在定义域内,对数函数为减函数.</p><p>3、下列函数中,为奇函数的是()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/156411642c7ba59.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/156411643238049.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/1564116437cc5f5.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/156411643c1ff56.png' /></li></ul><p>答 案:B</p><p>解 析:当f(-x)=-f(x),函数f(x)是奇函数,只有选项B符合.</p><p>4、设α是第三象限角,若<img src="https://img2.meite.com/questions/202303/15641164a2250e5.png" />,则sinα=()</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/1564116483e2d49.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/156411648920e99.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/156411648dc7387.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/156411649179a9b.png' /></li></ul><p>答 案:D</p><p>解 析:由于<img src="https://img2.meite.com/questions/202303/1564116825627fd.png" />,而α为第三象限角,故<img src="https://img2.meite.com/questions/202303/156411684ec6fe9.png" /></p><p class="introTit">主观题</p><p>1、在△ABC中,B=120°,BC=4,△ABC的面积为<img src="https://img2.meite.com/questions/202303/15641165ec55404.png" />,求AC.</p><p>答 案:由△ABC的面积为<img src="https://img2.meite.com/questions/202303/15641165ec55404.png" />得<img src="https://img2.meite.com/questions/202303/1564116bba3c98d.png" />所以AB =4.因此<img src="https://img2.meite.com/questions/202303/1564116be4bebd5.png" />所以<img src="https://img2.meite.com/questions/202303/1564116be967e8f.png" /></p><p>2、设函数f(x)=<img src="https://img2.meite.com/questions/202303/28642286431b211.png" /> (Ⅰ)求f(x)的单调区间; (Ⅱ)求 f(x)的极值</p><p>答 案:(Ⅰ)函数的定义域为<img src="https://img2.meite.com/questions/202303/28642286bee9cc3.png" /> <img src="https://img2.meite.com/questions/202303/28642286c7d68a9.png" /> (Ⅱ)<img src="https://img2.meite.com/questions/202303/28642286d3444c8.png" />  </p><p>3、为了测河的宽,在岸边选定两点A和B,望对岸标记物C,测得<img src="https://img2.meite.com/questions/202303/2864228db8c0e49.png" />AB=120m,求河的宽 <img src="https://img2.meite.com/questions/202303/2864228dd64bdcb.png" /></p><p>答 案:如图, <img src="https://img2.meite.com/questions/202303/2864228df3f06d3.png" /> ∵∠C=180°-30°-75°=75° ∴△ABC为等腰三角形,则AC=AB=120m 过C做CD⊥AB,则由Rt△ACD可求得CD=<img src="https://img2.meite.com/questions/202303/2864228e8a387f3.png" />=60m, 即河宽为60m  </p><p>4、设函数f(x)=xlnx+x.(I)求曲线y=f(x)在点((1,f(1))处的切线方程;<br />(II)求f(x)的极值.</p><p>答 案:(I)f(1)=1,f'(x)=2+lnx,故f'(1)=2.所以曲线y=f(x)在点(1,f(1))处的切线方程为y=2x-1.(II)令f'(x)=0,解得<img src="https://img2.meite.com/questions/202303/1564116d2d14a94.png" />当<img src="https://img2.meite.com/questions/202303/1564116d3d33026.png" />时,f'(x)<O;当<img src="https://img2.meite.com/questions/202303/1564116d6f6aec3.png" />时,f'(x)>O.故f(x)在区间<img src="https://img2.meite.com/questions/202303/1564116db9a0764.png" />单调递减,在区间<img src="https://img2.meite.com/questions/202303/1564116dc99fc91.png" />单调递增.因此f(x)在<img src="https://img2.meite.com/questions/202303/1564116ddb842d0.png" />时取得极小值<img src="https://img2.meite.com/questions/202303/1564116de4f1b79.png" /></p><p class="introTit">填空题</p><p>1、椭圆的中心在原点,一个顶点和一个焦点分别是直线x+3y-6与两坐标轴的交点,则此椭圆的标准方程为()  </p><p>答 案:<img src="https://img2.meite.com/questions/202303/286422989dd2b03.png" /></p><p>解 析:原直线方程可化为<img src="https://img2.meite.com/questions/202303/28642298bab2d76.png" />交点(6,0),(0,2). 当点(6,0)是椭圆一个焦点,点(0,2) 是椭圆一个顶点时,c=6,b=2,<img src="https://img2.meite.com/questions/202303/28642298d6bc461.png" />当点(0,2) 是椭圆一个焦点,(6,0) 是椭圆一个顶点时,c=2,b-6,<img src="https://img2.meite.com/questions/202303/28642298ef2aa6b.png" /></p><p>2、函数<img src="https://img2.meite.com/questions/202303/2864225857f0d64.png" />的图像与坐标轴的交点共有()  </p><p>答 案:2</p><p>解 析:当x=0时,y=<img src="https://img2.meite.com/questions/202303/286422587f2a68b.png" />-2=-1,故函数与y轴交于(0,-1)点,令y=0,则有<img src="https://img2.meite.com/questions/202303/28642258b372965.png" />故函数与x轴交于(1,0) 点,因此函数 <img src="https://img2.meite.com/questions/202303/28642258c6c51c8.png" />与坐标轴的交点共有 2个.</p>
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