2024年成考高起点《数学(文史)》每日一练试题03月30日

聚题库

03/30

单选题1、已知数列前n项和<img src="https://img2.meite.com/questions/202303/2964239ac0ef633.png" />则第5项的值是（）<ul><li>A：7</li><li>B：10</li><li>C：13</li><li>D：16</li></ul>答案：C解析：<img src="https://img2.meite.com/questions/202303/2964239b7a390c1.png" /><img src="https://img2.meite.com/questions/202303/2964239b8153001.png" />=3n-2.当n=5时，<img src="https://img2.meite.com/questions/202303/2964239b9b9086f.png" />=3×5-2=132、函数<img src="https://img2.meite.com/questions/202303/296423e9f4c42ba.png" />与y<img src="https://img2.meite.com/questions/202303/296423e9fce2f9b.png" />的图像之间的关系是 <ul><li>A：关于原点对称</li><li>B：关于x轴对称</li><li>C：关于直线 y=1对称</li><li>D：关于y轴对称</li></ul>答案：D解析：<img src="https://img2.meite.com/questions/202303/296423ea4eab0e4.png" /><img src="https://img2.meite.com/questions/202303/296423ea5d59f26.png" />关于y轴对称，3、已知向量a=(3,4),b=(0,-2),则cos=() <ul><li>A：<img src='https://img2.meite.com/questions/202303/296423b170c2f95.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/296423b17508b91.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/296423b17967146.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/296423b17e2de84.png' /></li></ul>答案：B解析：因为a=(3,4),b=(0,-2), <img src="https://img2.meite.com/questions/202303/296423b1f8241e7.png" /> 4、任选一个两位数,它恰好是10的倍数的概率是（）<ul><li>A：<img src='https://img2.meite.com/questions/202303/2964239a9b1203b.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/2964239a9f21f1c.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/2964239aa80509d.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/2964239aa374c5f.png' /></li></ul>答案：C解析：由已知条件可知此题属于等可能事件.两位数(正整数)从10~99共有90个,则n=90,是10的倍数的两位数共有9个，则m=9，<img src="https://img2.meite.com/questions/202303/2964239b50cf34a.png" />故任选一个两位数(正整数),它恰好是10的倍数的概率是<img src="https://img2.meite.com/questions/202303/2964239b6932ff5.png" />主观题1、如图：已知在△ADC中，∠C=90°，∠D=30°，∠ABC=45°，BD=20，求AC(用小数表示，保留一位小数) <img src="https://img2.meite.com/questions/202303/296423e7b58f8d3.png" /> 答案：如图 <img src="https://img2.meite.com/questions/202303/296423e7cbcb7ab.png" /> <img src="https://img2.meite.com/questions/202303/296423e7dd72c9c.png" /> 2、设函数f(x)<img src="https://img2.meite.com/questions/202303/296423a66bbdb95.png" />且f'(-1)=-36 (Ⅰ)求m (Ⅱ)求f(x)的单调区间答案：(Ⅰ)由已知得f'=<img src="https://img2.meite.com/questions/202303/296423a74f41b7f.png" /> 又由f'(-1)=-36得 6-6m-36=-36 故m=1. (Ⅱ)由(Ⅰ)得f'(x)=<img src="https://img2.meite.com/questions/202303/296423a792d1aff.png" /> 令f'(x)=0，解得<img src="https://img2.meite.com/questions/202303/296423a7b14cf3f.png" /> 当x<-3时，f'(x)>0; 当-3<x<2时，f'(x)<0; 当x>2时，f'(x)>0; 故f(x)的单调递减区间为(-3,2)，f(x)的单调递增区间为(-∞,-3),(2,+∞) 3、每亩地种果树20棵时,每棵果树收入90元,如果每亩增种一棵,每棵果树收入就下降3元,求使总收入最大的种植棵数. 答案：设每亩增种x棵,总收入味y元，则每亩种树(20+x)棵，由题意知增种x棵后每棵收入为（60-3x）则有y=(90-3x)(20+x) 整理得y=<img src="https://img2.meite.com/questions/202303/286422a66eea349.png" />+30x+1800 配方得y=<img src="https://img2.meite.com/questions/202303/286422a688a5af1.png" />+1875 当x=5时，y有最大值，所以每亩地最多种25棵4、在△ABC中,已知三边 a、b、c 成等差数列,且最大角∠A是最小角的2倍, a: b :c. 答案：<img src="https://img2.meite.com/questions/202303/296423b0ae0659d.png" />填空题1、从某班的一次数学测试卷中任意抽出10份,其得分情况如下:81,98,43,75,60,55,78,84,90,70,则这次测验成绩的样本方差是（） 答案：252.84解析：<img src="https://img2.meite.com/questions/202303/296423a0854ced5.png" /> <img src="https://img2.meite.com/questions/202303/296423a08a3c5bd.png" /> <img src="https://img2.meite.com/questions/202303/296423a0a201208.png" /><img src="https://img2.meite.com/questions/202303/296423a0b18ce79.png" /><img src="https://img2.meite.com/questions/202303/296423a0c014f0f.png" /><img src="https://img2.meite.com/questions/202303/296423a0ca81d80.png" /><img src="https://img2.meite.com/questions/202303/296423a0d0c2d44.png" />=252.84 2、函数y=<img src="https://img2.meite.com/questions/202303/296423a650306d1.png" />的定义域是（）答案：[1,+∞)解析：要是函数y=<img src="https://img2.meite.com/questions/202303/296423a6e097a67.png" />有意义，需使<img src="https://img2.meite.com/questions/202303/296423a6f397863.png" /><img src="https://img2.meite.com/questions/202303/296423a703abb7f.png" /> 所以函数的定义域为{x|x≥1}=[1,+∞)