2024年成考高起点《数学(文史)》每日一练试题03月18日
聚题库
03/18
<p class="introTit">单选题</p><p>1、甲袋内有2个白球3个黑球,乙袋内有3个白球1个黑球,现从两个袋内各摸出1个球,摸出的两个球都是白球的概率是</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/296423a4a7e7671.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/296423a4ac33ac7.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/296423a4b6c43e4.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/296423a4b010c99.png' /></li></ul><p>答 案：C</p><p>解 析：由已知条件可知此题属于相互独立同时发生的事件，从甲袋内摸到白球的概率为P(A)=<img src="https://img2.meite.com/questions/202303/296423a58023a72.png" />乙袋内摸到白球的概率为<img src="https://img2.meite.com/questions/202303/296423a597803ee.png" />，所以现从两袋中各提出一个球，摸出的两个都是白球的概率为<img src="https://img2.meite.com/questions/202303/296423a5b36a46a.png" /><img src="https://img2.meite.com/questions/202303/296423a5b70decc.png" /></p><p>2、设α是三角形的一个内角，若<img src="https://img2.meite.com/questions/202303/1464102637baabc.png" />，则sinα=（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/146410277c73796.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/14641027838231f.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/1464102788b3139.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/146410278d24d10.png' /></li></ul><p>答 案：D</p><p>解 析：由题知0＜α＜兀，而<img src="https://img2.meite.com/questions/202303/1464102b0581dad.png" />，故<img src="https://img2.meite.com/questions/202303/1464102b0b41884.png" />，因此<img src="https://img2.meite.com/questions/202303/1464102b0fe7c88.png" />.</p><p>3、任选一个两位数,它恰好是10的倍数的概率是（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/2964239a9b1203b.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/2964239a9f21f1c.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/2964239aa80509d.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/2964239aa374c5f.png' /></li></ul><p>答 案：C</p><p>解 析：由已知条件可知此题属于等可能事件.两位数(正整数)从10~99共有90个,则n=90,是10的倍数的两位数共有9个，则m=9，<img src="https://img2.meite.com/questions/202303/2964239b50cf34a.png" />故任选一个两位数(正整数),它恰好是10的倍数的概率是<img src="https://img2.meite.com/questions/202303/2964239b6932ff5.png" /></p><p>4、函数<img src="https://img2.meite.com/questions/202303/296423e9f4c42ba.png" />与y<img src="https://img2.meite.com/questions/202303/296423e9fce2f9b.png" />的图像之间的关系是
</p><ul><li>A：关于原点对称</li><li>B：关于x轴对称</li><li>C：关于直线 y=1对称</li><li>D：关于y轴对称</li></ul><p>答 案：D</p><p>解 析：<img src="https://img2.meite.com/questions/202303/296423ea4eab0e4.png" /><img src="https://img2.meite.com/questions/202303/296423ea5d59f26.png" />关于y轴对称，</p><p class="introTit">主观题</p><p>1、在△ABC中,已知三边 a、b、c 成等差数列,且最大角∠A是最小角的2倍, a: b :c.
</p><p>答 案：<img src="https://img2.meite.com/questions/202303/296423b0ae0659d.png" /></p><p>2、设函数f(x)<img src="https://img2.meite.com/questions/202303/296423a66bbdb95.png" />且f'(-1)=-36
(Ⅰ)求m
(Ⅱ)求f(x)的单调区间</p><p>答 案：(Ⅰ)由已知得f'=<img src="https://img2.meite.com/questions/202303/296423a74f41b7f.png" /> 又由f'(-1)=-36得
6-6m-36=-36
故m=1.
(Ⅱ)由(Ⅰ)得f'(x)=<img src="https://img2.meite.com/questions/202303/296423a792d1aff.png" />
令f'(x)=0，解得<img src="https://img2.meite.com/questions/202303/296423a7b14cf3f.png" />
当x<-3时，f'(x)>0;
当-3<x<2时，f'(x)<0;
当x>2时，f'(x)>0;
故f(x)的单调递减区间为(-3,2)，f(x)的单调递增区间为(-∞,-3),(2,+∞)
</p><p>3、已知直线l的斜率为1，l过抛物线C：<img src="https://img2.meite.com/questions/202303/1564111c54b8a1f.png" />的焦点，且与C交于A,B两点.<br />(I）求l与C的准线的交点坐标；<br />(II）求|AB|．</p><p>答 案：(I）C的焦点为<img src="https://img2.meite.com/questions/202303/1564111ce1ece45.png" />，准线为<img src="https://img2.meite.com/questions/202303/1564111cf077c15.png" />由题意得l的方程为<img src="https://img2.meite.com/questions/202303/1564111d17b9087.png" />因此l与C的准线的交点坐标为<img src="https://img2.meite.com/questions/202303/1564111d41e334d.png" />(II）由<img src="https://img2.meite.com/questions/202303/1564111d60deac4.png" />得<img src="https://img2.meite.com/questions/202303/1564111d70ccff6.png" />设A（x1,y1）.B（x2,y2），则<img src="https://img2.meite.com/questions/202303/1564111da85efe1.png" />因此<img src="https://img2.meite.com/questions/202303/1564111db86701f.png" /></p><p>4、已知等差数列<img src="https://img2.meite.com/questions/202303/296423eaf9717d6.png" />前n项和<img src="https://img2.meite.com/questions/202303/296423eb032d219.png" />
（Ⅰ）求通项<img src="https://img2.meite.com/questions/202303/296423eb1a4ebf5.png" />的表达式
（Ⅱ）求<img src="https://img2.meite.com/questions/202303/296423eb26c2214.png" />的值
</p><p>答 案：（Ⅰ）当n=1时，由<img src="https://img2.meite.com/questions/202303/296423eb432a645.png" />得<img src="https://img2.meite.com/questions/202303/296423eb5068b03.png" /> <img src="https://img2.meite.com/questions/202303/296423eb59a45cd.png" />
<img src="https://img2.meite.com/questions/202303/296423eb6100c03.png" />
也满足上式，故<img src="https://img2.meite.com/questions/202303/296423eb755b7df.png" />=1-4n（n≥1）
（Ⅱ）由于数列<img src="https://img2.meite.com/questions/202303/296423eb93e2df0.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423eba5a3367.png" />公差为d=-4的等差数列，所以<img src="https://img2.meite.com/questions/202303/296423ebc29c045.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423ebe5ba947.png" />公差为d=-8，项数为13的等差数列，于是由等差数列前n项和公式得：
<img src="https://img2.meite.com/questions/202303/296423ec1ac9811.png" /><img src="https://img2.meite.com/questions/202303/296423ec20a013e.png" />
</p><p class="introTit">填空题</p><p>1、点（4,5)关于直线y=x的对称点的坐标为（）</p><p>答 案：(5,4)</p><p>解 析：点(4,5)关于直线y=x的对称点为（5,4).</p><p>2、设<img src="https://img2.meite.com/questions/202303/2964239c3b4ac2f.png" />则<img src="https://img2.meite.com/questions/202303/2964239c42d80d7.png" /></p><p>答 案：-1</p><p>解 析：<img src="https://img2.meite.com/questions/202303/2964239ca8a1cc9.png" /> <img src="https://img2.meite.com/questions/202303/2964239cb367f80.png" />
<img src="https://img2.meite.com/questions/202303/2964239cc4f078f.png" />
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