2024年成考高起点《数学(理)》每日一练试题02月06日
聚题库
02/06
<p class="introTit">单选题</p><p>1、已知全集U=R，A={x|x≥1}，B={x|-1<x≤2},则<img src="https://img2.meite.com/questions/202303/2864229bae18781.png" /></p><ul><li>A：{x|x≤2}</li><li>B：{x|x<2}</li><li>C：{x|-1<x≤2}</li><li>D：{x|-1<x<1}</li></ul><p>答 案：A</p><p>解 析：补集运算应明确知道是否包括端点.A在U中的补集是x<1， <img src="https://img2.meite.com/questions/202303/2864229c436e804.png" />
<img src="https://img2.meite.com/questions/202303/2864229c50ac610.png" /><img src="https://img2.meite.com/questions/202303/2864229c574ae01.png" /><img src="https://img2.meite.com/questions/202303/2864229c5e8c7e7.png" />
</p><p>2、5名高中毕业生报考3所院校,每人只能报一所院校,则有（）种不同的报名方法
</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/28642253cbeb828.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/28642253cf87ee2.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/28642253d82d2a0.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/28642253d319585.png' /></li></ul><p>答 案：C</p><p>解 析：将院校看成元素,高中生看成位置,由重复排列的元素、位置的条件口诀: “元素可挑剩，位置不可缺”，重复排列的种数共有<img src="https://img2.meite.com/questions/202303/286422548fe3345.png" />种,即将元素的个数作为底数,位置的个数作为指数.即:元素(院校)的个数为 3,位置(高中生)的个数为5,共有<img src="https://img2.meite.com/questions/202303/28642254ad8b5e0.png" />种。
</p><p>3、已知向量a=(3,4),向量 b=(0,-2),则cos的值为（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/2864228b79d4590.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/2864228b7f2183c.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/2864228b82e5ed4.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/2864228b86922f8.png' /></li></ul><p>答 案：B</p><p>解 析：求cos<a,b>可直接用公式cos<a,b><img src="https://img2.meite.com/questions/202303/2864228c5310ae5.png" /> a·b=(3,4)·(0,-2)=3×0+4×(-2)=8,<img src="https://img2.meite.com/questions/202303/2864228c9dda4eb.png" />
</p><p>4、函数<img src="https://img2.meite.com/questions/202303/15641164b43c663.png" />的反函数是（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/15641164d78e1fc.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/15641164de92884.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/15641164e5206d4.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/15641164e93e32e.png' /></li></ul><p>答 案：A</p><p>解 析：<img src="https://img2.meite.com/questions/202303/15641168660282b.png" />，由于x≤0，故<img src="https://img2.meite.com/questions/202303/1564116881a60a4.png" />把x与y互换，得所求反函数为<img src="https://img2.meite.com/questions/202303/15641168ab18774.png" /></p><p class="introTit">主观题</p><p>1、设函数f(x)=<img src="https://img2.meite.com/questions/202303/28642286431b211.png" />
(Ⅰ)求f(x)的单调区间;
(Ⅱ)求 f(x)的极值</p><p>答 案：(Ⅰ)函数的定义域为<img src="https://img2.meite.com/questions/202303/28642286bee9cc3.png" /> <img src="https://img2.meite.com/questions/202303/28642286c7d68a9.png" />
(Ⅱ)<img src="https://img2.meite.com/questions/202303/28642286d3444c8.png" />
</p><p>2、在△ABC中，B=120°,BC=4,△ABC的面积为<img src="https://img2.meite.com/questions/202303/15641165ec55404.png" />，求AC.</p><p>答 案：由△ABC的面积为<img src="https://img2.meite.com/questions/202303/15641165ec55404.png" />得<img src="https://img2.meite.com/questions/202303/1564116bba3c98d.png" />所以AB =4.因此<img src="https://img2.meite.com/questions/202303/1564116be4bebd5.png" />所以<img src="https://img2.meite.com/questions/202303/1564116be967e8f.png" /></p><p>3、已知数列<img src="https://img2.meite.com/questions/202303/286422511c19556.png" />的前n项和<img src="https://img2.meite.com/questions/202303/2864225128dc6e0.png" />
求证：<img src="https://img2.meite.com/questions/202303/286422513318bbb.png" />是等差数列，并求公差和首项。
</p><p>答 案：<img src="https://img2.meite.com/questions/202303/286422514f41b7b.png" /> <img src="https://img2.meite.com/questions/202303/28642251563e39b.png" />
</p><p>4、某工厂每月生产x台游戏机的收入为R(x)=<img src="https://img2.meite.com/questions/202303/28642259676bd4d.png" />+130x-206(百元)，成本函数为C(x)=50x+100(百元)，当每月生产多少台时,获利润最大?最大利润为多少?
</p><p>答 案：利润 =收入-成本， L(x)=R(x)-C(x)=<img src="https://img2.meite.com/questions/202303/28642259c06a284.png" />+130x-206-(50x+100)=<img src="https://img2.meite.com/questions/202303/28642259e2077b7.png" />+80x-306
法一：用二次函数<img src="https://img2.meite.com/questions/202303/28642259fb36916.png" />当a<0时有最大值
<img src="https://img2.meite.com/questions/202303/2864225a14ed5aa.png" />是开口向下的抛物线，有最大值
<img src="https://img2.meite.com/questions/202303/2864225a2c75330.png" />
法二：用导数来求解
<img src="https://img2.meite.com/questions/202303/2864225a43988b8.png" />
因为x=90是函数在定义域内唯一驻点
所以x=90是函数的极大值点，也是函数的最大值点，其最大值为L（90）=3294
</p><p class="introTit">填空题</p><p>1、函数<img src="https://img2.meite.com/questions/202303/28642285dd68e2c.png" />的定义域是（）</p><p>答 案：<img src="https://img2.meite.com/questions/202303/28642285f367786.png" /></p><p>解 析：<img src="https://img2.meite.com/questions/202303/28642285fcec513.png" /><img src="https://img2.meite.com/questions/202303/2864228601aa2da.png" />所以函数<img src="https://img2.meite.com/questions/202303/286422860d8135c.png" />的定义域是<img src="https://img2.meite.com/questions/202303/286422861644b62.png" /></p><p>2、<img src="https://img2.meite.com/questions/202303/2864228ce0438da.png" />的展开式是（）</p><p>答 案：<img src="https://img2.meite.com/questions/202303/2864228d0c480eb.png" /></p><p>解 析：<img src="https://img2.meite.com/questions/202303/2864228d4197eb2.png" /><img src="https://img2.meite.com/questions/202303/2864228d47da120.png" /><img src="https://img2.meite.com/questions/202303/2864228d5101aa0.png" /><img src="https://img2.meite.com/questions/202303/2864228d5bc2a57.png" /><img src="https://img2.meite.com/questions/202303/2864228d65510b6.png" /></p>
