2024年成考高起点《数学(文史)》每日一练试题02月02日

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02/02
<p class="introTit">单选题</p><p>1、点(2,4)关于直线y=x的对称点的坐标为()  </p><ul><li>A:(4,2)</li><li>B:(-2,-4)</li><li>C:(-2,4)</li><li>D:(-4,-2)</li></ul><p>答 案:A</p><p>解 析:点(2,4) 关于直线y=x对称的点为(4,2)</p><p>2、甲袋内有2个白球3个黑球,乙袋内有3个白球1个黑球,现从两个袋内各摸出1个球,摸出的两个球都是白球的概率是</p><ul><li>A:<img src='https://img2.meite.com/questions/202303/296423a4a7e7671.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/296423a4ac33ac7.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/296423a4b6c43e4.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/296423a4b010c99.png' /></li></ul><p>答 案:C</p><p>解 析:由已知条件可知此题属于相互独立同时发生的事件,从甲袋内摸到白球的概率为P(A)=<img src="https://img2.meite.com/questions/202303/296423a58023a72.png" />乙袋内摸到白球的概率为<img src="https://img2.meite.com/questions/202303/296423a597803ee.png" />,所以现从两袋中各提出一个球,摸出的两个都是白球的概率为<img src="https://img2.meite.com/questions/202303/296423a5b36a46a.png" /><img src="https://img2.meite.com/questions/202303/296423a5b70decc.png" /></p><p>3、已知向量a=(3,4),b=(0,-2),则cos=()  </p><ul><li>A:<img src='https://img2.meite.com/questions/202303/296423b170c2f95.png' /></li><li>B:<img src='https://img2.meite.com/questions/202303/296423b17508b91.png' /></li><li>C:<img src='https://img2.meite.com/questions/202303/296423b17967146.png' /></li><li>D:<img src='https://img2.meite.com/questions/202303/296423b17e2de84.png' /></li></ul><p>答 案:B</p><p>解 析:因为a=(3,4),b=(0,-2), <img src="https://img2.meite.com/questions/202303/296423b1f8241e7.png" />  </p><p>4、已知数列前n项和<img src="https://img2.meite.com/questions/202303/2964239ac0ef633.png" />则第5项的值是()</p><ul><li>A:7</li><li>B:10</li><li>C:13</li><li>D:16</li></ul><p>答 案:C</p><p>解 析:<img src="https://img2.meite.com/questions/202303/2964239b7a390c1.png" /><img src="https://img2.meite.com/questions/202303/2964239b8153001.png" />=3n-2.当n=5时,<img src="https://img2.meite.com/questions/202303/2964239b9b9086f.png" />=3×5-2=13</p><p class="introTit">主观题</p><p>1、每亩地种果树20棵时,每棵果树收入90元,如果每亩增种一棵,每棵果树收入就下降3元,求使总收入最大的种植棵数.  </p><p>答 案:设每亩增种x棵,总收入味y元,则每亩种树(20+x)棵,由题意知增种x棵后每棵收入为(60-3x) 则有y=(90-3x)(20+x) 整理得y=<img src="https://img2.meite.com/questions/202303/286422a66eea349.png" />+30x+1800 配方得y=<img src="https://img2.meite.com/questions/202303/286422a688a5af1.png" />+1875 当x=5时,y有最大值,所以每亩地最多种25棵</p><p>2、设函数<img src="https://img2.meite.com/questions/202303/1564111c65679ad.png" /><br />(I)求f'(2);<br />(II)求f(x)在区间[一1,2]的最大值与最小值.</p><p>答 案:(I)因为<img src="https://img2.meite.com/questions/202303/1564111dd4eb139.png" />,所以f'(2)=3×2<sup>2</sup>-4=8.(II)因为x<-1,f(-1)=3.<img src="https://img2.meite.com/questions/202303/1564111ea39de57.png" />f(2)=0.<br />所以f(x)在区间[一1,2]的最大值为3,最小值为<img src="https://img2.meite.com/questions/202303/1564111eb99e49a.png" /></p><p>3、已知三角形的一个内角是<img src="https://img2.meite.com/questions/202303/296423b4bf816f0.png" />,面积是<img src="https://img2.meite.com/questions/202303/296423b4cd02d83.png" />周长是20,求各边的长.  </p><p>答 案:设三角形三边分别为a,b,c,∠A=60°, <img src="https://img2.meite.com/questions/202303/296423b55f6ab61.png" />  </p><p>4、在△ABC中,B=120°,C=30°,BC=4,求△ABC的面积.</p><p>答 案:因为A= 180°-B-C=30°,所以AB = BC=4.因此△ABC的面积<img src="https://img2.meite.com/questions/202303/1564111c8c97743.png" /></p><p class="introTit">填空题</p><p>1、函数y=<img src="https://img2.meite.com/questions/202303/296423a650306d1.png" />的定义域是()</p><p>答 案:[1,+∞)</p><p>解 析:要是函数y=<img src="https://img2.meite.com/questions/202303/296423a6e097a67.png" />有意义,需使<img src="https://img2.meite.com/questions/202303/296423a6f397863.png" /><img src="https://img2.meite.com/questions/202303/296423a703abb7f.png" /> 所以函数的定义域为{x|x≥1}=[1,+∞)  </p><p>2、不等式<img src="https://img2.meite.com/questions/202303/286422a55aeabe3.png" />的解集是()  </p><p>答 案:<img src="https://img2.meite.com/questions/202303/286422a56c78cca.png" /></p><p>解 析:<img src="https://img2.meite.com/questions/202303/286422a578989db.png" />或<img src="https://img2.meite.com/questions/202303/286422a57faa8bc.png" />或<img src="https://img2.meite.com/questions/202303/286422a58777039.png" /></p>
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