2024年成考高起点《数学(文史)》每日一练试题01月27日
聚题库
01/27
<p class="introTit">单选题</p><p>1、函数f(x)=<img src="https://img2.meite.com/questions/202303/296423e87e65604.png" />当x∈[-2,+∞)时是增函数，当x∈(-∞,-2]时是减函数，则f(1)=()
</p><ul><li>A：-3</li><li>B：13</li><li>C：7</li><li>D：由m而定的常数</li></ul><p>答 案：B</p><p>解 析：由题意知抛物线的对称轴为x=-2， <img src="https://img2.meite.com/questions/202303/296423e91d09887.png" />
</p><p>2、设M=<img src="https://img2.meite.com/questions/202303/286422a42729326.png" />那么（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/286422a43031e0b.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/286422a433cfa72.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/286422a4397f784.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/286422a43e0967d.png' /></li></ul><p>答 案：D</p><p>解 析：<img src="https://img2.meite.com/questions/202303/286422a4b8b4342.png" /> M是集合，a为元素，{a}为集合，元素与集合的关系是<img src="https://img2.meite.com/questions/202303/286422a4d2b7178.png" />集合与集合的关系是<img src="https://img2.meite.com/questions/202303/286422a4dc161c3.png" /><img src="https://img2.meite.com/questions/202303/286422a4e20a711.png" /><img src="https://img2.meite.com/questions/202303/286422a4e6eebab.png" />
</p><p>3、函数f(x)=<img src="https://img2.meite.com/questions/202303/2964239ea542b2e.png" />的单调增区间是（）</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/2964239ebc3fa1e.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/2964239ec1364eb.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/2964239ec5da4ec.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/2964239eca429dd.png' /></li></ul><p>答 案：A</p><p>解 析：<img src="https://img2.meite.com/questions/202303/2964239f6c29fd7.png" />中的<img src="https://img2.meite.com/questions/202303/2964239f78240cc.png" /><img src="https://img2.meite.com/questions/202303/2964239f8391b8a.png" />的减区间就为f(x)的增区间，设u(x)=<img src="https://img2.meite.com/questions/202303/2964239fa51c8e3.png" />当x∈R时，u(x)>0,函数u(x)在<img src="https://img2.meite.com/questions/202303/2964239fd320fd2.png" />是减函数， <img src="https://img2.meite.com/questions/202303/2964239fdcba7f4.png" />上是增函数
故f(x)=<img src="https://img2.meite.com/questions/202303/2964239ff389b79.png" />的单调增区间为<img src="https://img2.meite.com/questions/202303/2964239ffd784d3.png" />
ps：关于复合函数的问题要逐步分清每一层次的函数的图像和性质,再结合起来考虑整体,有时也可画出部分函数的图像来帮助分析和理解.
</p><p>4、函数<img src="https://img2.meite.com/questions/202303/296423e9f4c42ba.png" />与y<img src="https://img2.meite.com/questions/202303/296423e9fce2f9b.png" />的图像之间的关系是
</p><ul><li>A：关于原点对称</li><li>B：关于x轴对称</li><li>C：关于直线 y=1对称</li><li>D：关于y轴对称</li></ul><p>答 案：D</p><p>解 析：<img src="https://img2.meite.com/questions/202303/296423ea4eab0e4.png" /><img src="https://img2.meite.com/questions/202303/296423ea5d59f26.png" />关于y轴对称，</p><p class="introTit">主观题</p><p>1、设函数f(x)<img src="https://img2.meite.com/questions/202303/296423a66bbdb95.png" />且f'(-1)=-36
(Ⅰ)求m
(Ⅱ)求f(x)的单调区间</p><p>答 案：(Ⅰ)由已知得f'=<img src="https://img2.meite.com/questions/202303/296423a74f41b7f.png" /> 又由f'(-1)=-36得
6-6m-36=-36
故m=1.
(Ⅱ)由(Ⅰ)得f'(x)=<img src="https://img2.meite.com/questions/202303/296423a792d1aff.png" />
令f'(x)=0，解得<img src="https://img2.meite.com/questions/202303/296423a7b14cf3f.png" />
当x<-3时，f'(x)>0;
当-3<x<2时，f'(x)<0;
当x>2时，f'(x)>0;
故f(x)的单调递减区间为(-3,2)，f(x)的单调递增区间为(-∞,-3),(2,+∞)
</p><p>2、如图：已知在△ADC中，∠C=90°，∠D=30°，∠ABC=45°，BD=20，求AC(用小数表示，保留一位小数)
<img src="https://img2.meite.com/questions/202303/296423e7b58f8d3.png" />
</p><p>答 案：如图 <img src="https://img2.meite.com/questions/202303/296423e7cbcb7ab.png" />
<img src="https://img2.meite.com/questions/202303/296423e7dd72c9c.png" />
</p><p>3、已知等差数列<img src="https://img2.meite.com/questions/202303/296423eaf9717d6.png" />前n项和<img src="https://img2.meite.com/questions/202303/296423eb032d219.png" />
（Ⅰ）求通项<img src="https://img2.meite.com/questions/202303/296423eb1a4ebf5.png" />的表达式
（Ⅱ）求<img src="https://img2.meite.com/questions/202303/296423eb26c2214.png" />的值
</p><p>答 案：（Ⅰ）当n=1时，由<img src="https://img2.meite.com/questions/202303/296423eb432a645.png" />得<img src="https://img2.meite.com/questions/202303/296423eb5068b03.png" /> <img src="https://img2.meite.com/questions/202303/296423eb59a45cd.png" />
<img src="https://img2.meite.com/questions/202303/296423eb6100c03.png" />
也满足上式，故<img src="https://img2.meite.com/questions/202303/296423eb755b7df.png" />=1-4n（n≥1）
（Ⅱ）由于数列<img src="https://img2.meite.com/questions/202303/296423eb93e2df0.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423eba5a3367.png" />公差为d=-4的等差数列，所以<img src="https://img2.meite.com/questions/202303/296423ebc29c045.png" />是首项为<img src="https://img2.meite.com/questions/202303/296423ebe5ba947.png" />公差为d=-8，项数为13的等差数列，于是由等差数列前n项和公式得：
<img src="https://img2.meite.com/questions/202303/296423ec1ac9811.png" /><img src="https://img2.meite.com/questions/202303/296423ec20a013e.png" />
</p><p>4、已知三角形的一个内角是<img src="https://img2.meite.com/questions/202303/296423b4bf816f0.png" />，面积是<img src="https://img2.meite.com/questions/202303/296423b4cd02d83.png" />周长是20,求各边的长.
</p><p>答 案：设三角形三边分别为a,b,c,∠A=60°， <img src="https://img2.meite.com/questions/202303/296423b55f6ab61.png" />
</p><p class="introTit">填空题</p><p>1、函数<img src="https://img2.meite.com/questions/202303/296423b01fb70b9.png" />的图像与坐轴的交点共有（）个
</p><p>答 案：2</p><p>解 析：当x=0，<img src="https://img2.meite.com/questions/202303/296423b06fa2850.png" />故函数与y轴交于(0,-1)点;令y=0,则有<img src="https://img2.meite.com/questions/202303/296423b0803e06f.png" />故函数与工轴交于(1,0)点,因此函数<img src="https://img2.meite.com/questions/202303/296423b08e0e38c.png" />与坐标轴的交点共有2个</p><p>2、函数f(x)=<img src="https://img2.meite.com/questions/202303/296423b497a799f.png" />在区间[-3,3]上的最大值为（）
</p><p>答 案：4</p><p>解 析：这题考的是高次函数的最值问题，可用导数来求函数在区间[-3,3]上的最值。<img src="https://img2.meite.com/questions/202303/296423b5082e922.png" /> 列出表格<img src="https://img2.meite.com/questions/202303/296423b517619c0.png" />
由上表可知函数在[-3,3]上，在x=1点处有最大值为4.
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